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PD0312 · Problem 26

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Problem

The function ff is defined by f(x)=axbf(x)=a^x-b, where a>0a>0. For a positive constant cc, f(c)=8andf(2c)=190.f(c)=8\qquad\text{and}\qquad f(2c)=190. What is f(3c)+bf(c)+b?\frac{f(3c)+b}{f(c)+b}?
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